Home Analysis • Posn(R) and Eisenstein Series by Jay Jorgenson, Serge Lang (auth.)

Posn(R) and Eisenstein Series by Jay Jorgenson, Serge Lang (auth.)

By Jay Jorgenson, Serge Lang (auth.)

Posn(R) and Eisenstein Series presents an creation, requiring minimum necessities, to the research on symmetric areas of optimistic certain actual matrices in addition to quotients of this area through the unimodular workforce of crucial matrices. The process is gifted in very classical phrases and comprises fabric on specified services, significantly gamma and Bessel services, and specializes in convinced mathematical elements of Eisenstein series.

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2. From the first order decomposition of Z ∈ SPosn :    w 0 1 0   Z= −1/(n−1) x In−1 0 w V with w ∈ R+ , x ∈ Rn−1 , V ∈ Posn−1 , we have the measure decomposition dw (1) dxdµn−1 (V ) . w Proof. This comes from the same type of partial coordinates Jacobian computation as in Sect. 2. n/2 dµ(1) n (Z) = w Next we tabulate the subgroups of SLn (R) which will allow inductive decompositions of various things on SLn (R). We let: Gn = SLn (R) Γn = SLn (Z) Gn,1 = subgroup of Gn leaving the first unit vector t e1 fixed, so Gn,1 consists of all matrices 1 x 0 g with x ∈ Rn−1 and g ∈ SLn−1 (R) .

0 . . ann 1/2 0 . . ann A full Iwasawa decomposition for Y can be written in the form 1 Y = [u(X)]A = T t T with T = u(X)A 2 . 1 1 2 Then tii = aii2 and 2dtii /tii = daii /aii . Furthermore, tij = xij ajj for i < j. Then 1 2 dxij + a term with daij . 4. Let Y = [u(X)]A. Then n n i−(n+1)/2 dµn (Y ) = aii i=1 Similarly, on the other side: daii aii i=1 dxij . 5. Let Y = A[u(X)]. Then n n −i+(n+1)/2 dµn (Y ) = aii i=1 daii aii i=1 dxij . i

4. Suppose d¯ g is the symmetrically normalized measure. For ϕ continuous (say) and in L1 (R+ ), we have: ϕ(t xx)dx = Vn Rn ϕ([ ]Z)dµ(1) n (Z), Γ\SPosn =0 ϕ([ ]Z)dµ(1) n (Z). = ζ(n) Γn \SPosn prim Proof. Let f (x) = ϕ(t xx) and apply Siegel’s formula to f . 2) =0 ϕ([ ]g t g)d¯ g = Γ\G =0 ϕ([ ]Z)dµ(1) n (Z) = Γ\SPosn =0 by the normalization (9) thus concluding the proof of the first version, summing over all = 0. 2. 5. For ϕ on R+ guaranteeing convergence (for example, assume that ϕ ∈ Cc (R+ )) ϕ([ ]Z)dµ(1) n (Z) = Vn−1 Γn \SPosn prim ϕ(r)rn/2 dr .

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